Several important acids can be classified as polyprotic acids, which can lose more than one H+ ion when they act as Bronsted acids. Diprotic acids, such as sulfuric acid (H2SO4), carbonic acid (H2CO3), hydrogen sulfide (H2S), chromic acid (H2CrO4), and oxalic acid (H2C2O4) have two acidic hydrogen atoms. Triprotic acids, such as phosphoric acid (H3PO4) and citric acid (C6H8O7), have three.
There is usually a large difference in the ease with which these acids lose the first and second (or second and third) protons. When sulfuric acid is classified as a strong acid, students often assume that it loses both of its protons when it reacts with water. That isn't a legitimate assumption. Sulfuric acid is a strong acid because Ka for the loss of the first proton is much larger than 1. We therefore assume that essentially all the H2SO4 molecules in an aqueous solution lose the first proton to form the HSO4-, or hydrogen sulfate, ion.
H2SO4(aq) + H2O(l) H3O+(aq) + HSO4-(aq) |
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Ka1 = 1 x 103 |
But Ka for the loss of the second proton is only 10-2 and only 10% of the H2SO4 molecules in a 1 M solution lose a second proton.
HSO4-(aq) + H2O(l) H3O+(aq) + SO42-(aq) |
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Ka2 = 1.2 x 10-2 |
H2SO4 only loses both H+ ions when it reacts with a base, such as ammonia.
The large difference between the values of Ka for the sequential loss of protons by a polyprotic acid is important because it means we can assume that these acids dissociate one step at a timean assumption known as stepwise dissociation.
As every next dissociation constant is smaller, usually it is enough to do the pH calculation treating acid as if it was only monoprotic (ie omitting effects of the next dissociation step). Further if the acid is weak even in respect to the first dissociation step and the second constants is much smaller, we can neglect second dissociation step completely.
The most general definition of acids and bases, which encompasses the Arrhenius and Bronsted-Lowry definitions is due to our old friend, Lewis and his dot structures. A Lewis acid is defined to be any species that accepts lone pair electrons. A Lewis base is any species that donates lone pair electrons. Thus, H+ is a Lewis acid, since it can accept a lone pair, while OH- and NH3 are Lewis bases, both of which donate a lone pair:
Interestingly, however, is that species which have no hydrogen to donate (a la the Bronsted-Lowry scheme) can still be acids according to the Lewis scheme. As an example, consider the molecule BF3. If we determine Lewis structure of BF3, we find that B is octet deficient and can accept a lone pair. Thus it can act as a Lewis acid.
Acid-Base Strength and Structure:
Oxoacids have the hydrogen atoms in the acid bonded to oxygen. The more oxygen atoms there are in the acid the stronger the acid will be.
If we compared acid strength with acids where the atoms bonded to hydrogen were in the same period, the difference in the size of the atoms would not be significant. In that case the electronegativity becomes the deciding factor. The greater the electronegativity of the atom the stronger will be the acid.
Identify the Lewis acid and Lewis base in each of the following reactions:
(a) SnCl4(s) A + 2 Cl–(aq)B ó SnCl62–(aq)
(b) Hg2+(aq)A + 4 CN–(aq)B ó Hg(CN)42–(aq)
(c) Co3+(aq)A + 6 NH3(aq)B ó Co(NH3)63+(aq)
Predict the relative strengths of the following groups of oxoacids:
a) HClO, HBrO, and HIO.; HIO > HBrO > HClO (More e- going down the group)
b) HNO3 and HNO2. HNO3 (more oxygens)> HNO2
c) H3PO3 and H3PO4 H3PO4 (more oxygens)> H3PO3
Selenious acid (H2SeO3), a diprotic acid, has K1 = 3.0 x 10-3 and K2 = 5.0 x 10-8. What is the [HSeO4-] of a 0.50 M solution of selenious acid?
Two deprotonations:
H2SeO3 + H2O ó HSeO3- + H3O+
I 0.50 0 0
C -x +x +x
E 0.50- x x x
3.0 x 10-3 = x2/0.50-x x2 + 3.0x10-3x – 0.0015 = 0 x = 0.037 = [HSeO4-]
Second Deprotonation:
HSeO3- + H2O ó SeO32- + H3O+
I 0.037 0 0
C -x +x +x
E 0.037- x x x
5.0 x 10-8 = x2/0.037-x x2 + 5.0x 10-8x - 1.85 x 10-9 x = 4.3 x 10-5
[HSeO3-] = 0.037 – 4.3x10-5 = ~0.037